x^2+(x+1)(x+2)=92

Solution for x^2+(x+1)(x+2)=92 equation:

x^2+(x+1)(x+2)=92

We move all terms to the left:

x^2+(x+1)(x+2)-(92)=0

We multiply parentheses ..

x^2+(+x^2+2x+x+2)-92=0

We get rid of parentheses

x^2+x^2+2x+x+2-92=0

We add all the numbers together, and all the variables

2x^2+3x-90=0

a = 2; b = 3; c = -90;
Δ = b2-4ac
Δ = 32-4·2·(-90)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-27}{2*2}=\frac{-30}{4}
=-7+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+27}{2*2}=\frac{24}{4}
=6
$